笨方法

def make_row_to_column(a):
    b = []
    for item in range(len(a[0])):
        r = []
        for j in range(len(a)):
            r.append(a[j][item])
        b.append(r)
    return b

🐍PyTricks

def row_2_column(row_list):
    return map(list,zip(*row_list))


if __name__ == '__main__':
    nest_list = [[_ for _ in range(5)] for i in range(4)] 
    print(row_2_column(nest_list)) 
    # [[0, 0, 0, 0], [1, 1, 1, 1], [2, 2, 2, 2], [3, 3, 3, 3], [4, 4, 4, 4]]

注意在Python3中返回的是一个<map object at 0x000002674CC62688>，需要再用list() 方法转一下。

参考